Module 5, Assignment 7

Send a screen shot of the spectrum of 41 Cygnus to Chris Martin. Explain what your temperature estimate is for this star.

12 comments:

  1. I measured peak wavelength as 4020.5 nm and
    by using Wien`s law, I calculated temperature of 41 Cygnus as 7189K.

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  2. Wein’s Law:
    λmax = (2.89 × 10-3 K m)/T
    Derived for temperature:
    T = (2.89 × 10-3 K m)/ λmax


    Wavelength from Graphical Analysis = 4020 Angstroms or 4000 when considering significant figures

    Conversion
    4000 Angstroms = 400 nm = 4.00 x 10-7 m

    Calcualtion:
    T= (2.89 × 10-3 K m)/ 4.00 x 10-7 m
    T= 7225 K

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  3. I zoomin on the spectra for 41 cygnus to and used the pointer to read the point at the peak. The reading was 4020.5435 A and 6.891e-14 ergs.... Using Wein's equation, the temperature was calculated to be 7190 k.

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  4. I got 4020.54 angstrom (6.891 x10^-14) for the peak . Using wien's law, the temperature for 41 cygnus is 7207.4K . My temperature wil be 7200K

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  5. From the graphical analysis 3, my peak wavelength is 4020.54 angstrom (6.891E-14 ergs). Using Wien's Displacement Law : T = 2.897 E+7 / lambda max, the temperature is 7205 K. My estimated value for the temperature of 41 cygnus star is 7200K

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  6. I got the same peak wavelength (4021 angstrom) using Graphical Analysis. Plugging in this value to Wien's law formula, my temperature is 7192K.

    In the simulator (in module 2), I got a temperature of 7210K. Using 2 sigfig, I have 7200K for 41_cyg

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  7. My peak wavelength of the spectrum is 4020.54 angstrom. Applying Wien's law, the computed temperature is around 7200K (using 2SF)

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  8. Using the examine tool of Graphical Analysis, the highest peak wavelength is 4020.54 angstrom. Using the online calculator for Wien's law, my temperature for this star is 7207K. Using 2Sigfig I got 7200K for 41_cyg

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  9. Using the examine tool of graphical analysis, I estimated that the peak should correlate to the highest peak on the graph which was at 4020.54 angstrom. Using Wien's equation, I calculated the temperature of 41 Cygnus to be 7200 K rounding to 2 sig. figs.

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  10. I got 4020A for the peak wavelength. Using the conversion factor of 1.0x10^10 meters/A, the peak wavelength is 4.02x10^-7 meters, or in the violet part of the visible spectrum. The temperature in Kelvin is (2.89x10^-3 Km)/(4.02x10^-7m) = 7190 K.

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  11. For 41_Cyg I estimated the peak to be about
    4020 Angstroms . Using Wien’s law

    T (max K) = 2.90x10^-3 m•K/4.02x10^-7 m

    T = 7200 K

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  12. From GA, the peak is 4020.5 angstrom and using Wien's law, I got a temperature of 7200K (expressed in 2 SF)

    ReplyDelete